Calling function within .each()

Question

I would like to repeat the chained events starting at .animate() from inside itself (indicated by comment). What is the correct way to write this?

$("div").each(function(i, e){  
  $(this).animate({ left: $(this).parent().width() }, d[i], "linear",
      function(){ $(this).css({left: -parseInt($(this).css("width")) })
      //would like to call function at this stage
   });
})

This ended up working:

   $("div").each( v = function(i, e){  
     $(this).animate({ left: $(this).parent().width() }, d[i], "linear",
         function(){ $(this).css({left: -parseInt($(this).css("width")) })
         v();
      });
   });

mattsven · Accepted Answer · 2011-04-20 19:57:43Z

2

Like this?

$("div").each(function(i, e){  
  $(this).animate({ left: $(this).parent().width() }, d[i], "linear",
      v = function(i){
            $(this).css({left: -parseInt($(this).css("width")) })
            if(i == null) v(1);
        });
})

Not sure I fully understood your goal...

answered Apr 20, 2011 at 19:57

mattsven

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1 Comment

jeffreynolte Over a year ago

This is just about what I needed to do, it helped me to complete the function correctly. posted above.

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