How to fix program closing right after input statement

Question

I'm making a simple text game in Python 3, and I tried to make an input statement, but when I answer it, the program closes. How can I fix this?

I've tried Googling it, but I just see "program closes straight after opening it".

def startgame():
    print("####################")
    ign = input("Type a name. ")
    print("####################")
    namedecision = input("You have picked " + ign + ".\nAre you sure you want\nto keep this name? (Y/N) ")
    if namedecision == ['y','Y']:
        # put game func
        print("####################")
    if namedecision == ['n', 'N']:
        ign = input("Type a name. ")
        namedecision = input("You have picked " + ign + ".")
        print("####################")
        # game func

startgame()

I expect that if I typed Y or N it would execute the proper functions.

is your program really indented like this? If so, you need to correct that. — mauve
– mauve, Commented Aug 5, 2019 at 19:44
No, it's actually indented properly. Do you mean the interpreter? — defrood
– defrood, Commented Aug 5, 2019 at 19:46

ophunt · Accepted Answer · 2019-08-05 19:48:15Z

2

Your if statements are always returning false because your input will always be a string, and you are comparing it to a list. Change your == for in in order to check if a string (or any other type) is in a list.

Corrected code:

def startgame():
    print("####################")
    ign = input("Type a name. ")
    print("####################")
    namedecision = input("You have picked " + ign + ".\nAre you sure you want\nto keep this name? (Y/N) ")
    if nameDecision in ['y','Y']:
        # put game func
        print("####################")
    elif nameDecision in ['n', 'N']:
        ign = input("Type a name. ")
        namedecision = input("You have picked " + ign + ".")
        print("####################")

startgame()

edited Aug 5, 2019 at 19:48

answered Aug 5, 2019 at 19:46

ophunt

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ophunt Over a year ago

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