The issue with in_array statement

Question

I want to display certain URL links on a product page only for certain products and for certain countries. Initially, I retrieve the IP of the country then check, the product ID. If the product ID is in the array I display Link 1 if users are from Canada and Link 2 if they are from the US. The problem is that it is not showing anything. Nothing happens within the if statement that contains in_array and not sure what I am doing wrong.

<?php
if ($currentCountry =="CA" || $currentCountry =="US") 
{
    $p_id = $_product->getId();   
    $include_id = array(546, 125,135);
    ?>
    <style>
    .choose-local {
        display: flex;
    }
    .data-section {
        min-width: 33%;
    }
    .choose-local .data-section span {
        float: left;
    }
    </style>
    <?php
    if (in_array($p_id,$include_id, TRUE)) 
    {

        ?>
        <div class='choose-local'>
            <div class='data-section'>
                <span style="">Available Locally from :</span>
            </div>
            <div class="data-section">
                <?php 
                    if ($currentCountry =="CA") 
                    { 
                        ?>
                        <span>Link 1<a href='https://www.link1.com'>[Order from here]</a></span>
                        <?php
                    }

                    if ($currentCountry =="US") 
                    { 
                        ?>        
                        <span>Link 2<a href='https://www.link2.com'>[Order from here]</a></span>
                        <?php 
                    } 
                ?>      
            </div>
        </div>
    <?php 
    }
}
?>

what a result of $p_id = $_product->getId(); if it's string, cast to integer — splash58
– splash58, Commented Aug 8, 2019 at 11:01
If you var_dump($p_id), what do you get? Is it a string? If so, try remove the third parameter from in_array(). That bool is strict mode which checks type — Brett Gregson
– Brett Gregson, Commented Aug 8, 2019 at 11:01
check your this variable $p_id = $_product->getId(); this might be String type int and in your in_array($p_id,$include_id, TRUE) you strictly checking the type. Try this $p_id = intval($_product->getId()); will work — BlackXero
– BlackXero, Commented Aug 8, 2019 at 11:02
$p_id = intval($_product->getId()); works!!! Thanks a lot guys for pointing me in the right direction. — bertassa
– bertassa, Commented Aug 8, 2019 at 11:18

yogesh sharma · Accepted Answer · 2019-08-08 12:00:54Z

1

check weather your $p_id is string or int

<?php
                                $currentCountry = "CA";
if ($currentCountry =="CA" || $currentCountry =="US") 
{
    $p_id = 125;   
    $include_id = array(546, 125,135);
    ?>
    <style>
    .choose-local {
        display: flex;
    }
    .data-section {
        min-width: 33%;
    }
    .choose-local .data-section span {
        float: left;
    }
    </style>
    <?php
    if (in_array($p_id,$include_id, TRUE)) 
    {

        ?>
        <div class='choose-local'>
            <div class='data-section'>
                <span style="">Available Locally from :</span>
            </div>
            <div class="data-section">
                <?php 
                    if ($currentCountry =="CA") 
                    { 
                        ?>
                        <span>Link 1<a href='https://www.link1.com'>[Order from here]</a></span>
                        <?php
                    }

                    if ($currentCountry =="US") 
                    { 
                        ?>        
                        <span>Link 2<a href='https://www.link2.com'>[Order from here]</a></span>
                        <?php 
                    } 
                ?>      
            </div>
        </div>
    <?php 
    }
}
?>

answered Aug 8, 2019 at 12:00

yogesh sharma

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1 Comment

bertassa Over a year ago

thanks the users who commented yesterday had already suggested that. It was returning a string not an integer. This is why it was not working.

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