Pick Index of Array and group to new array by Index of Array

Question

I have an array, that each index will follow another index, and the index will not follow same index. After that index is current and index will be followed by index is target

This is code for python

list_value = [1,2,3]
for current in range(len(list_value)):
   for target in range(len(list_value)):

     if current == target: continue
     list_target.append(target)

expected output is {current:0, target:[1,2,0,2,0,1]}

but the result what i need is

{current:0, target:[1,2]}
{current:1, target:[0,2]}
{current:2, target:[0,1]}

I only add new target and repeatedly till the length of list_value done, I need help, please

thanks a lot

dangee1705 · Accepted Answer · 2019-08-10 10:37:17Z

1

If I understand your problem correctly, I believe what you want to do is this:

list_value = [1, 2, 3]
for current in range(len(list_value)):
    result = {"current": current, "target": []}
    for target in range(len(list_value)):
        if current != target:
            result["target"].append(target)
    print(result) # do something with each result here

This should print

{'current': 0, 'target': [1, 2]}
{'current': 1, 'target': [0, 2]}
{'current': 2, 'target': [0, 1]}

answered Aug 10, 2019 at 10:37

dangee1705

3,5402 gold badges27 silver badges45 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

dangee1705 Over a year ago

@Subhanshuja if this worked could you +1 it and accept it as the answer please

Subhanshuja Over a year ago

accept and i'm still new in stackoverflow, i cannot add +1

Collectives™ on Stack Overflow

Pick Index of Array and group to new array by Index of Array

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related