Accessing Json value of variable with a colon (:) in between using Php

Question

I need to access the value of a variable element in Json, the problem however the variable has a colon (:) and i keep getting undefined variable every time.

{#370 ▼
  +"im:name": {#371 ▶}
  +"im:image": array:3 [▶]
  +"im:itemCount": {#380 ▶}
  +"im:price": {#381 ▶}
  +"im:contentType": {#385 ▶}
  +"rights": {#387 ▶}
  +"title": {#388 ▶}
  +"link": {#390 ▶}
  +"id": {#391 ▶}
  +"im:artist": {#393 ▶}
  +"category": {#396 ▶}
  +"im:releaseDate": {#397 ▶}
}

for example $feed->category is okay , but anything with : in between like $feed->im:category throws an error.

Could be worth reading stackoverflow.com/questions/4887300/… stackoverflow.com/questions/250679/… and a few others may also help. — Nigel Ren
– Nigel Ren, Commented Aug 12, 2019 at 5:20
simplexml_load_string in some cases does not capture all the details neede — TechPotter
– TechPotter, Commented Aug 12, 2019 at 6:04
I would be surrised that it misses anything and converting it to JSON can cause all sorts of problems. — Nigel Ren
– Nigel Ren, Commented Aug 12, 2019 at 6:12

Dharman · Accepted Answer · 2019-08-11 14:43:32Z

6

Use curly brace syntax

$feed->{'im:category'}

answered Aug 11, 2019 at 14:43

Dharman♦

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Dharman · Accepted Answer · 2021-04-03 11:35:53Z

0

Try to json_decode it and force the use of associative arrays with JSON_OBJECT_AS_ARRAY.

edited Apr 3, 2021 at 11:35

Dharman♦

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answered Aug 11, 2019 at 13:26

KHALDOUN

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