Generating file paths by adding file names onto a string

Question

The user inputs a string signifying a folder name, then hardcoded file names are added onto that string from a list to create two absolute file paths.

The first file path is ok, but the second adds the filename onto the already added first filename.

files = ["file1.txt", "file2.txt"]
path = str(input("Path: "))
new_paths = []

for file in files:
    path += r"\{0}".format(file)
    new_paths.append(path)

print(new_paths)

Supposing an user input of:

C:\\Users\User\Desktop\file_folder

The file paths added onto the new_paths list are:

['C:\\\\Users\\Users\\Desktop\\file_folder\\file1.txt', 'C:\\\\Users\\Users\\Desktop\\file_folder\\file1.txt\\file2.txt']

As opposed to the desired result of:

['C:\\\\Users\\Users\\Desktop\\file_folder\\file1.txt', 'C:\\\\Users\\Users\\Desktop\\file_folder\\file2.txt']

Possible duplicate of Platform-independent file paths?

zwer
– zwer

2019-08-16 09:54:36 +00:00
Commented Aug 16, 2019 at 9:54 — zwer
– zwer, Commented Aug 16, 2019 at 9:54

Sparky05 · Accepted Answer · 2019-08-16 09:54:50Z

2

You are overwriting your variable path, try

files = ["file1.txt", "file2.txt"]
path = str(input("Path: "))
new_paths = []

for file in files:
    file_path = path + r"\{0}".format(file)
    new_paths.append(file_path)

print(new_paths)

answered Aug 16, 2019 at 9:54

Sparky05

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Yaroslav Kornachevskyi · Accepted Answer · 2019-08-16 09:59:35Z

1

You are updating the same variable. Just use it:

for file in files:
    new_paths.append(path + r"\{0}".format(file))

print(new_paths)

answered Aug 16, 2019 at 9:59

Yaroslav Kornachevskyi

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PySaad · Accepted Answer · 2019-08-16 10:07:05Z

1

You can do with below mentioned code -

[os.path.join(path, x) for x in files] 
# prints you entered path+files

Complete Code:

import argparse
files = ["file1.txt", "file2.txt"]

def create_argparse():
    parser = argparse.ArgumentParser()

    parser.add_argument('-p','--path',
                        help='path')
    return parser.parse_args()

def main():
    args = create_argparse()
    path = args.path

    print [os.path.join(path, x) for x in files]

if __name__ == '__main__':
    sys.exit(main())

Reference:

https://docs.python.org/3/library/argparse.html

answered Aug 16, 2019 at 10:07

PySaad

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