my code keeps showing syntax error in my elif/else statements

Question

I'm trying to make a basic pig latin translator but the editor keeps showing me a syntax error.

ay = "ay"

way = "way"

consonants = ("b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z")

vowels = ("a", "e", "i", "o", "u")

user_word = input("Enter your word here: ")

first_letter = user_word[0]

first_letter = str(first_letter)

first_letter = first_letter.upper()

if first_letter in consonants:

        print(first_letter + "is a consonant.")

remove_first_letter = user_word[1:]

pig_latin = remove_first_letter + first_letter + ay

print("The word in Pig Latin is " + pig_latin)

elif first_letter in vowels:

        print(first_letter + "is a vowel.")

pig_latin = user_word + way

print("The word in Pig Latin is " + pig_latin)

else:

        print("I don\'t know what" + first_letter + "is.")

This is what i have come up with. The exact error message that it shows is:

File "<ipython-input-33-8e1536233f19>", line 14

    elif first_letter in vowels:

       ^

SyntaxError: invalid syntax

Welcome to SO! The indentation is invalid. Please fix and thanks (you can't have an elif just hanging out without an associated if). — ggorlen
– ggorlen, Commented Aug 24, 2019 at 3:12
when i used the indentation, it showed indentation error, so instead i just removed indentation. Before the elif statement, the code is running fine with the if statement. after the elif statement, its throwing an error (?) — Shruti Sinha
– Shruti Sinha, Commented Aug 24, 2019 at 3:22
The if is syntactically valid and its block ends and the outer main scope resumes. But then, out of nowhere, there's an elif without an if before it. A minimal reproducible example of this error is the following program (run it for yourself): elif True: print("hello world"). — ggorlen
– ggorlen, Commented Aug 24, 2019 at 3:31

Tordek · Accepted Answer · 2019-08-24 03:25:56Z

3

Python is an indentation-dependent language. elif and else need to be at the same depth as if, and whatever statement depends on the condition needs to be indented further.

For example:

if first_letter in consonants:
    print(first_letter + "is a consonant.")
    remove_first_letter = user_word[1:]
    pig_latin = remove_first_letter + first_letter + ay
    print("The word in Pig Latin is " + pig_latin)
elif first_letter in vowels:
    print(first_letter + "is a vowel.")
    pig_latin = user_word + way
    print("The word in Pig Latin is " + pig_latin)
else:
    print("I don\'t know what" + first_letter + "is.")

answered Aug 24, 2019 at 3:25

Tordek

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