i.e if ArrayList contains coordinates {0, 0} remove them.
Code test below fails as expected.
ArrayList<int[]> array = new ArrayList<>();
int[] arr1 = new int[]{0, 0};
int[] arr2 = new int[]{1, 1};
array.add(arr1);
array.add(arr2);
System.out.println("Before " + array.contains(arr1)); // true
int[] arr3 = new int[]{0, 0};
array.remove(arr3);
System.out.println("After " + array.contains(arr1)); //true
You can use removeIf like so :
array.removeIf(a-> a[0] == 0 && a[1] == 0);
or you can use :
array.removeIf(a -> Arrays.equals(a, new int[]{0, 0}));
Of if you want to remove all the arrays which contains only zeros you can use :
array.removeIf(a -> Arrays.stream(a).allMatch(value -> value == 0));
After the edit of the OP the solution can be like so :
array.removeIf(a -> Arrays.equals(a, arr3));
remove() does
System.out.println("After " + array.contains(arr1)); //true- actually that printsAfter false, since you are removing the exact same array instance you added to the List.array.contains(arr3)just before removing itremoveonly removes first found element (if it would work with arrays)