jquery - pattern matching

Question

I've been trying to use the jquery match() function, but I'm not able to get anything I try to work...

Basically, I'm trying to match any string between parentheses:

(sample) (pokemon) (su54gar99)

... etc.

Tried this (the latest attempt... not sure how many I've gone through at this point...)

$('.acf').each(function() {
                var ac = $(this);
                ac.data('changed', false);
                ac.data('alias', 'ac-real-');
                ac.data('rx',  /\s*\(\s+\)\s*/i);
                ac.data('name', ac.attr('name'));
                ac.data('id', ac.attr('id'));
                ac.data('value', ac.val());
        });

manojlds · Accepted Answer · 2011-04-25 15:50:29Z

2

Why are you using \s ? It matches any whitespace character

Use a regular expression like below:

\(.+\)

answered Apr 25, 2011 at 15:50

manojlds

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3 Comments

Nova-Love-94044 Over a year ago

Thanks, I figured it out like 1 minutes after I posted... Thank you, though!

ridgerunner Over a year ago

Never use the dot when there is a more precise expression (in this case: [^()]). The expression: $.+$ fails if there are multiple sets of parentheses. Note that the lazy dot version: $.+?$ also fails if the parentheses are nested. Use: $[^()]*$ to safely match only innermost sets of parentheses.

manojlds Over a year ago

It was just a suggestion to correct what was wrong. Anyway, thanks for your input.

Martin Bories · Accepted Answer · 2011-04-25 16:00:53Z

1

I suggest your fault is, that "\s" only stands for whitespace characters, but not for normal characters ;).

Second, for finding EACH and not stopping after 1 result, add the "g" (for global) modifier.

Try something like this:

var text = "(sample) (pokemon) (su54gar99)";
var found = text.match(/\s*\(([a-z,0-9]*)\)/ig);
$.each(found, function(i, v) {
    alert(i+" = "+v);
});

Works with at least the given example ;).

TIP: Visit: http://www.w3schools.com/jsref/jsref_obj_regexp.asp Best side for learning RegEx, in my opinion :P.

answered Apr 25, 2011 at 16:00

Martin Bories

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1 Comment

mattsven Over a year ago

Curses, beat me. /^$.|\d*?$$/ <- any downfalls?

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