Regex to FindAll chains of strings until a dot with python

Question

I need the regex expression gives to me the word before the : and all until a . The right output will be

['Socios: Norberto Alejandro PERONACE, 16/8/1973', 'Joaquin: jaja']

Here is my code:

text = "Esc. 7, Fº 10, 14/1/2019, Esc. M. Paula Corallo, Reg. 1525, Socios: Norberto Alejandro PERONACE, 16/8/1973. Joaquin: jaja."

if re.findall(r":", text):
    print(re.findall(r"\w+: \w+.\Z", text))
else:
    print("Match not found")

it's cut the output to the first word instead of continiuos to the dot @Sweeper — Martin Bouhier
– Martin Bouhier, Commented Sep 5, 2019 at 18:59

Wiktor Stribiżew · Accepted Answer · 2019-09-05 19:01:39Z

5

You may use

re.findall(r'\S+:[^.]+', text)

See the regex demo

Details

\S+ - 1+ non-whitespace chars
: - a colon
[^.]+ - 1+ non-dot chars.

See also the Python demo.

edited Sep 5, 2019 at 19:01

answered Sep 5, 2019 at 18:58

Wiktor Stribiżew

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