class Outer{
public void Method(){
int i=10;
System.out.println(i);
Class InsideMethod{
//
}
}
Question : How can I call InsideMethod object outside of the method
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Could you provide an example?Alberto Zaccagni– Alberto Zaccagni2011-04-26 10:06:53 +00:00Commented Apr 26, 2011 at 10:06
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4 Answers
This snippet illustrates the various possibilities:
public class Outer {
void onlyOuter() { System.out.println("111"); }
void common() { System.out.println("222"); }
public class Inner {
void common() { System.out.println("333"); }
void onlyInner() {
System.out.println("444");// Output: "444"
common(); // Output: "333"
Outer.this.common(); // Output: "222"
onlyOuter(); // Output: "111"
}
}
}
Note:
- A method of inner class hides a similarly named method of the outer class. Hence, the
common();call dispatches the implementation from the inner class. - The use of the
OuterClass.thisconstruct for specifying that you want to dispatch a method from the outer class (to bypass the hiding) - The call
onlyOuter()dispatches the method fromOuterClassas this is the inner-most enclosing class that defines this method.
Comments
If I've understood correctly what you want, you could do:
OuterClass.this
answered Apr 26, 2011 at 10:06
Alberto Zaccagni
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Comments
defined inside a method of an outer class
If its defined inside a method then its scope is limited to that method only.
2 Comments
Samarth2011
we can call : new ClassName().Method();
Harry Joy
Yes we can. But we can not access variables inside that method.
From what I've understood of your question... (see the example below), the instance of class 'Elusive' defined within a method of an outer class cannot be referenced from outside of method 'doOuter'.
public class Outer {
public void doOuter() {
class Elusive{
}
// you can't get a reference to 'e' from anywhere other than this method
Elusive e = new Elusive();
}
public class Inner {
public void doInner() {
}
}
}
