Transform ServletInputStream to String

Question

I am trying to get the body of a HttpServletRequest in a String. What's the best elegant way to do so?

Use request.getInputStream() and stackoverflow.com/questions/309424/… — skaffman
– skaffman, Commented Apr 26, 2011 at 17:07
I wish I could do that @skaffman, however I must read the request body twice. Once to get a json object and the next one to get the string and I always get stream is already closed. Any thoughts? — tsunade21
– tsunade21, Commented Apr 27, 2011 at 8:23
tsunade21, your comment doesn't make sense. The answer above tells you how to turn your input stream into a string. Needing to read the same stream twice is very likely a bug. Just use the resulting string in both places. — James Moore
– James Moore, Commented Jul 28, 2011 at 22:06
@James Moore, i think i didn't explain myself well before. I had to read the same stream twice because I was using jackson mapping that was reading the stream automatically without giving me any control whatsoever. I finally fixed it, using gson instead of jackson mapping. — tsunade21
– tsunade21, Commented Sep 7, 2011 at 13:59
@JamesMoore is right, reading the stream twice is a bug. You read a Stream from a source you cannot control, from your user's browser. There's simply no way to tell that client "hey, would you send your data once again, please?" — Michael
– Michael, Commented Jan 5, 2014 at 16:25

siledh · Accepted Answer · 2014-06-13 07:36:44Z

19

String requestStr = IOUtils.toString(request.getInputStream());

answered Jun 13, 2014 at 7:36

siledh

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Comments

Aritz · Accepted Answer · 2016-10-13 10:58:22Z

2

Other way, using Guava:

ByteSource.wrap(ByteStreams.toByteArray(request.getInputStream()))
    .asCharSource(Charsets.UTF_8).read()

See also:

answered Oct 13, 2016 at 10:58

Aritz

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