have this string:
$var = "30.5x120.8 (test desc here)";
I need to get out 30.5 and 120.8 with a regular expression.. any help?? Thx
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If your regex questions are recurring, check out regular-expressions.info to learn the syntax, or stackoverflow.com/questions/89718/… for tools to craft them.mario– mario2011-04-27 13:33:56 +00:00Commented Apr 27, 2011 at 13:33
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4 Answers
preg_match_all('~\d+(?:\.\d+)?~', $string, $matches);
var_dump($matches[0]);
3 Comments
Alix Axel
@Ste: What about
30.5x.2? Is that a thing you want to support?
Ste
@Alix Axel: I don't think, but is possible replace .2 with 0.2 ?
NikiC
@Ste: Sure you can replace it. Just do
$string = preg_replace('(?<!\d)\.\d+', '0$0', $string); before you run the code above.$var = "30x120 (test desc here)";
preg_match_all('/^(\d+)x(\d+)/', $var, $matches);
var_dump($matches)
Output
array(3) {
[0]=>
array(1) {
[0]=>
string(6) "30x120"
}
[1]=>
array(1) {
[0]=>
string(2) "30"
}
[2]=>
array(1) {
[0]=>
string(3) "120"
}
}
Update
also work for 17.5x17.5 ?
Here is one which will...
/^(\d+(?:\.\d+)?)x(\d+(?:\.\d+)?)/
1 Comment
James C
I think
preg_match() would make more sense (and make the output array easier to parse) than preg_match_all() as there's only one occurence of the pattern in the subject string.preg_match('/^(\d+)x(\d+)/', '30x120 (test desc here)', $result);
and use $result[1] and $result[2]
2 Comments
James C
meh - posted near identically at the same time as @Kevin
Matthieu Napoli
It's often a question of seconds :p
The following should do the trick: /^(\d+)x(\d+)/
