How do I set up an if statement to use an array of conditionals as input in python

Question

First I check a given condition, as per a normal IF statement. If it is True, I need to scan all files for a single keyword. If it is not True, I need to scan all files for a set of keywords, which will have been supplied.

For my simple working example, rather than scanning file names in a directory, I simply search a string for the keywords.

test1 = "NotKeyWord"
password = "password"
password1 = "password1"
password2 = "password2"
password3 = "password3"

if test1.lower() == "keyword":
    condition = password
else:
    condition = [password1, password2, password3]

f = "password1_password2_password3_jibberish_E=mc2"
if condition in f:
    print("Problem solved")

If the keyword = "keyword" i.e., is singular, then this code works. Fine. However, I would like to make it so that if it is the other case, which requires knowing several keywords to grab the right file, I don't need to resort to explicitly writing out all the words.

For my purposes I could write

if password1 in f and password2 in f and password3 in f:
    print("problem solved")

But I am after a pythonic method, that will hopefully be generic enough to be able to handle an array of keywords that is of unknown length, and thus can't be hard coded.

Nebiyou Yismaw · Accepted Answer · 2019-09-28 03:29:15Z

4

This should work,

if all ( c in f for c in condition ):
    print("problem solved")

edited Sep 28, 2019 at 3:29

answered Sep 28, 2019 at 3:26

Nebiyou Yismaw

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2 Comments

Charlie Crown Over a year ago

The problem here is that if any of them are true, it passes, but I need ALL of them to be true

Nebiyou Yismaw Over a year ago

Okay, you can change to the condition to all(). I have edited it

John Gordon · Accepted Answer · 2019-09-28 03:27:40Z

3

Make condition always be a list, even if it only has one item:

if test1.lower() == "keyword":
    condition = [password]
else:
    condition = [password1, password2, password3]

Then use the all() function to check if all elements in condition are present in f:

if all(c in f for c in condition):
    print("problem solved")

This will work whether condition has one element, or ten, or a hundred.

answered Sep 28, 2019 at 3:27

John Gordon

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1 Comment

Charlie Crown Over a year ago

amen. I will flip a coin to see who gets it since Nebiyou had it too, just with the "any" rather than "all"

user2468968 · Accepted Answer · 2019-09-28 03:30:50Z

1

One way is:

if [x for x in condition if x in f]:
   ...

answered Sep 28, 2019 at 3:30

user2468968

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Comments

Jack Taylor · Accepted Answer · 2019-09-28 03:38:39Z

1

To make it easier for yourself, I would make a list of passwords in both cases. If test1 is the keyword then it just becomes a list of one.

if test1.lower() == "keyword":
    passwords = [password]
else:
    passwords = [password1, password2, password3]

Then you can use Python's built-in all function with a generator expression for the second condition.

f = "password1_password2_password3_jibberish_E=mc2"
if all(pw in f for pw in passwords):
    print("Problem solved")

answered Sep 28, 2019 at 3:38

Jack Taylor

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