How to display text from an array in a UITextView, I might just need the right string format?

Question

I have a multiline array which populates a tableview.

I now also want to use the array for a UITextView to display the string as it's currently being displayed.

I have it displaying everything as I want except for one of the symbols in the array which does not display as it should.

I feel like all I need is the right string format?

textView.text = String(format:"%@", array)

The code above is how I have it ALMOST working but the "x" symbol from the array is being substituted with "\U00d7"

The "x" does not appear to be an actual letter, (thus the "\U00d7") not an iOS one anyway.

Before adding the format "%@", the "x" symbol was being displayed as an x.

I want it to be displayed as I have entered it into the array rather than having to always change the "x" symbol for an iOS "X" symbol.

Can you demonstrate what king of input you have and what kind of output you are expecting??? e.g //Input array let array = ["a","b","c"] //Output string should be like "abc" or "a,b,c" or "a-b-c" etc — Syed Qamar Abbas
– Syed Qamar Abbas, Commented Oct 2, 2019 at 8:18
The output is identical to the input, the array is just holding multiline strings. — Superlative
– Superlative, Commented Oct 2, 2019 at 12:03
Like input = """1, 2, 3 1x 0.1%""" output = """1, 2, 3 1x 0.1%""". They need to also be on their own line. — Superlative
– Superlative, Commented Oct 2, 2019 at 12:17

Rajmund Zawiślak · Accepted Answer · 2019-10-02 08:40:30Z

3

Using String(format:_:) is not a good idea in this case. %@ does not work with utf8 encoding.

Try textView.text = array.joined() instead.

answered Oct 2, 2019 at 8:40

Rajmund Zawiślak

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3 Comments

Superlative Over a year ago

This method doesn't keep the lines separate. Each string has it's own line but with .joined() it's continuous. Good to know this way too as it has its own benefits.

Rajmund Zawiślak Over a year ago

@Superlative If you want newlines between each character, please use joined(separator:) instead.

Superlative Over a year ago

Thanks, much better, .joined(separator: String) and I made a string that was two lines.👍

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