Creating dictionary from the string using python

Question

I want to create a dictionary from the string like this below

" Car : 100 Bus: 200 Travel cost = 500 cycle : 10 bike : 50 "

and the output should look like below

{ 'car' : 100 , 'bus' : 200, 'Travel cost' : 500 ,  'cycle' : 10 , 'bike' : 50}

It has ":" and "=" in the string, so I am not understanding how to do, please help me. I tried:

Dict = dict((x.strip(), y.strip()) for x, y in (element.split(':') for element in string.split(' ')))

So what would you do is there wasn't = ? We're not a code writing service, please show what you tried and we can help from there! — h4z3
– h4z3, Commented Oct 14, 2019 at 11:43
looks like the answer is here stackoverflow.com/questions/988228/… — k2a
– k2a, Commented Oct 14, 2019 at 11:43
What is the purpose of the exercise? Read a string, sanitize the input and output to a dict? — Bruno Vermeulen
– Bruno Vermeulen, Commented Oct 14, 2019 at 11:45
@BrunoVermeulen Yes. I want to organise data and use it further — Tina
– Tina, Commented Oct 14, 2019 at 11:48
You might first try to split the text with regex: d = {m[0].strip() : int(m[1]) for m in re.findall("([^:=]+)[:=]\s+(\d+)", s)} — 001
– 001, Commented Oct 14, 2019 at 12:04

Bruno Vermeulen · Accepted Answer · 2019-10-14 12:43:54Z

1

It is quite hard to parse the string but let us assume the pattern in the string is:

'\D+ : \d+ \D+ : \d+'

where \D is a character and \d is a digit and divided by :, you may proceed as follows.

Sanitize the string and replace = with :
find all patterns for '\D+ : \d '
loop over the found pattern and convert to a dict

for example

import re
input_str = "Car : 100 Bus: 200 Travel cost = 500 cycle : 10 bike : 50 "
input_str = input_str.replace('=', ':')

dict_elements = re.findall(r'\D+ : \d+ ', input_str)

my_dict = {}
for element in dict_elements:
    key, val = element.split(':')
    key = key.strip()
    val = int(val.strip())
    my_dict[key] = val

print(my_dict)

actually a better solution dealing with possible spaces before and after the : is the following

import re
input_str = "Car:100 Bus: 200 Travel cost = 500 cycle: 10       bike      :50    "

dict_elements = re.findall(r'\s*(\D+)\s*[:=]\s*(\d+)\s*', input_str)

my_dict = {}
for element in dict_elements:
    my_dict[element[0].strip()] = int(element[1].strip())

print(my_dict)

Note I dealt with : or = in the search string of findall with [:=], while key is (\D+) and val is (\d+).

edited Oct 14, 2019 at 12:43

answered Oct 14, 2019 at 12:17

Bruno Vermeulen

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3 Comments

Hadi Farhadi Over a year ago

and where is bike : 50?

Bruno Vermeulen Over a year ago

ah, yes it needs a space after 50 ;). Probably the regex can be made much more clever to deal with the spaces!

Tina Over a year ago

Thank you so much fr inputs, it is very helpful

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