iterate a string based on another string

Question

I need to iterate variable Y, compare each iteration with variable sublist Variable X and create a new string with results.

Y = 'ABCEF'

X =[('A', 1),('B', 4),('C', 6),('D', 7),('E', 8),('F', 9),('G', 10),('H', 11),('I', 12),('J', 13),('K', 14),('L', 15),('M', 16)]

The result is below after iterating Y.

Z = '14689'

Can someone shade some light on the resolution of this.

Y = 'ABCEF'

X =[('A', 1),('B', 4),('C', 6),('D', 7),('E', 8),('F', 9),('G', 10),('H', 11),('I', 12),('J', 13),('K', 14),('L', 15),('M', 16)]
j <= len(X) - 1 
result = ''

for i in Y:
    if i in X[0][j]:
        result.append(X[j])
else: 
    j = j -1

Is X stored as a string (a la JSON) or is that a literal Python list? — Dai
– Dai, Commented Oct 21, 2019 at 1:05
So why is your question "iterate a string based on another string" when there's only 1 string? — Dai
– Dai, Commented Oct 21, 2019 at 1:07

blhsing · Accepted Answer · 2019-10-21 01:09:28Z

2

You can creating a mapping dict from X so that you can iterate through Y to map each character to its value before joining them into a new string:

mapping = dict(X)
Z = ''.join(str(mapping[c]) for c in Y)

Z becomes: '14689'

answered Oct 21, 2019 at 1:09

blhsing

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Habib Mohammed · Accepted Answer · 2019-10-21 01:28:41Z

0

y = 'ABCEF'
x =  [('A', 1),('B', 4),('C', 6),('D', 7),('E', 8),('F', 9),('G', 10),('H', 11),('I', 12),('J', 13),('K', 14),('L', 15),('M', 16)]
result = ''
for i in y: 
    for j in range(len(x)): 
        if i in x[j]:
            result += str(x[j][1])
            break
print(result)

the output will be 14689

answered Oct 21, 2019 at 1:28

Habib Mohammed

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1 Comment

John Over a year ago

Thank you Habib. Your solution is perfect!

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