How do I make multiple multi-item substitution based on index in python lists?

Question

Suppose I have a python list which looks like this:

a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

And a list of tuples with replacing instructions in the format (starting index, ending index, elements to replace with)

b = [ (2,5,["x","y"])  , (8,8,["z"]) ]

How do I make the substitution without messing with the indices? I've tried but can't get the right approach.

Expected output:

c = [0, 1, "x", "y", 6, 7, "z", 9]

kabanus · Accepted Answer · 2019-10-21 15:10:03Z

2

One way:

deleted = 0
for start, end, replacement in b:
    a[start - deleted:end + 1 - deleted] = replacement
    deleted += (end + 1 - start) - len(replacement)

edited Oct 21, 2019 at 15:10

answered Oct 21, 2019 at 15:04

kabanus

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