I want to overwrite value in field input with default attribute

Question

I need to enter my numeric value in input with currency. The field has a default attribute of 0.00.

this command does not change anything:

webElement.clear();
System.out.println("webElement.getAttribute("value")); //0,00

When I try to register my value equal to 803 in it, the field eventually gets a value of 0.00803, which is then rounded to 0.01:

webElement.sendKeys(text);
System.out.println("webElement.getAttribute("value")); //0,008003

The same thing happens when I use this command:

webElement.sendKeys(Keys.chord(Keys.COMMAND, "a", text)); //0,008003

Environment:

mac os
selenium-java-3
guava-25.0-jre
java 8
Google Chrome 77 version
ChromeDriver 77.0.3865.40

undetected Selenium · Accepted Answer · 2019-10-23 12:01:00Z

2

You can use executeScript() method from JavascriptExecutor as below :

 WebElement element = driver.findElement(By.xpath("enter the xpath here")); // you can use any locator
 JavascriptExecutor jse = (JavascriptExecutor)driver;
 jse.executeScript("arguments[0].value='enter the value here';", element);

edited Oct 23, 2019 at 12:01

undetected Selenium

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answered Oct 22, 2019 at 11:01

Shubham Jain

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