JSON cURL - invalid argument for foreach() - PHP

Question

I'm using this code:

<?php

$json_url = 'http://search.twitter.com/search.json?q=royal&wedding';

$ch = curl_init( $json_url );

$options = array(
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HTTPHEADER => array('Content-type: application/json')
);

curl_setopt_array( $ch, $options );

$result =  curl_exec($ch);

if (!empty($result)){
    $json = json_decode($result);
    foreach ($json->results[0]->text as $t){
        var_dump($t);
    }
}

?>

But i'm getting an invalid argument for the foreach??

Any ideas?

I don't know how json_decode works, but ,at the first glance, it seems you're searching for iterate the text value of the result[0] of your json output. This is wrong. Try to iterate $json results variable and inside the foreach cycle you can read the text value of the current item. — alesdario
– alesdario, Commented May 2, 2011 at 15:00

Yoshi · Accepted Answer · 2011-05-02 15:11:22Z

2

Try:

var_dump($json->results[0]->text);

And you'll get something like:

string(166) "RT @womensweard...

which means, you're trying to iterate over a string.

I guess, what you want is:

foreach ($json->results as $t){
  var_dump($t->text);
}

edited May 2, 2011 at 15:11

answered May 2, 2011 at 15:02

Yoshi

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Comments

Kaivosukeltaja · Accepted Answer · 2011-05-02 15:01:57Z

1

You're looping the text property of the first result. If you want to output the text for each result, you need to loop the results instead:

foreach ($json->results as $t){
    var_dump($t->text);
}

answered May 2, 2011 at 15:01

Kaivosukeltaja

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Comments

Marc B · Accepted Answer · 2011-05-02 14:57:57Z

0

Check that the CURL request succeeded:

$result = curl_exec($ch);

if ($result === FALSE) {
    die(curl_error($ch));
}

Then check that you actually received JSON data:

var_dump($result);

then check if the json_decode succeeded:

$json = json_decode($result);
if(is_null($json)) {
    die(json_last_error());
}

Then check if there actually is a 'results' entry in the json data:

if (!isset($json->results)) {
   die("No results section");
}

answered May 2, 2011 at 14:57

Marc B

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Comments

kapa · Accepted Answer · 2011-05-03 09:49:39Z

0

Idea: $result is not a valid JSON, and your $result is not an array.

edited May 3, 2011 at 9:49

kapa

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answered May 2, 2011 at 14:58

Wesley van Opdorp

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Comments

Tom D · Accepted Answer · 2014-01-13 14:13:15Z

0

Adding CURLOPT_SSL_VERIFYPEER => false to the CURL options within the performRequest() method in TwitterAPIExchange.php seems to solve it.

cf here

answered Jan 13, 2014 at 14:13

Tom D

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