How can I pass function's return value as parameter?

Question

I have lots of functions similar to FunctionOne. Difference in these is five = this.methodTwo(two, three, four, five). I don't want to repeat code. For doing that, how can I pass function's return value as parameter?

class MyClass {
    FunctionOne(one, two, three, four, five) {
        //some code here
        one = "my one";
        two = "my two";
        five = this.FunctionTwo(two, three, four, five); //How can I pass this as parameter
        one[five] = "something";
        return one;
    }
    FunctionThree(one, two, three, four, five) {
        //some code here
        one = "my one";
        two = "my two";
        five = this.FunctionFour(two, three, four, five); //Everything in FunctionThree is same as FunctionOne except this statement
        one[five] = "something";
        return one;
    }

    FunctionTwo(two, three, four, five) {
        //some code
        return five;
    }
}

Can you show examples of the repeated code? I don't get what you mean by "I pass function's return value as parameter". — Carcigenicate
– Carcigenicate, Commented Nov 13, 2019 at 17:01
@Carcigenicate added code to show example of the repeated code — user7331530
– user7331530, Commented Nov 13, 2019 at 17:12
You could pass the function to call as a parameter, like FunctionX(one, two, three, four, five, fn) {…} and could be called like x = FunctionX(h, i, j, k, l, FunctionOne) — Stephen P
– Stephen P, Commented Nov 13, 2019 at 17:14

Stephen P · Accepted Answer · 2019-11-13 19:26:03Z

1

One way to approach this would be to take the function as another parameter.

Similar to your FunctionOne, FunctionTwo etc. you could have FunctionX which does the common work and calls the passed function which, as a parameter, can be varied by the caller.

That would look something like this:

// added 'fn', the function to call, as the sixth parameter
FunctionX(one, two, three, four, five, fn) {
    //some code here
    one = "my one";
    two = "my two";
    five = fn(two, three, four, five);
    one[five] = "something";
    return one;
}

Now you can call this elsewhere like:

let x = FunctionX(h, i, j, k, l, FunctionOne);

answered Nov 13, 2019 at 19:26

Stephen P

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Carcigenicate · Accepted Answer · 2019-11-13 18:09:27Z

0

So,

By doing this:

five = this.FunctionTwo(two, three, four, five)

you calling function 'FunctionTwo' with params (two, three, four, five) and assigning result of function 'FunctionTwo' to variable 'five'

By doing this:
```
five = this.FunctionTwo
```

you are assigning function 'FunctionTwo' instance to variable 'five', but NOT calling it yet.

Basically later in the code you can do something like that:

five(two, three, four)

Not really clear what you want, but you can pass 'this' in to the 'FunctionTwo' and assign result to current object.

Ignore if nothing helps to you :)

edited Nov 13, 2019 at 18:09

Carcigenicate

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answered Nov 13, 2019 at 17:07

Dmitri Algazin

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