if statement not reading variables

Question

I wrote a program that reads data from a csv (saved as Unicode format in SQL Studio) and then does a few comparisons and prints out the results.

For some reason this simple if statement returns false eventhough when the data is printed it shows the correct results:

    foreach ($complete as $key => $val){    
    $INVOICE = 'INVOICE';
    $InvoiceType = $complete[$key][9];
    echo 'comparing' . $InvoiceType.'to'. $INVOICE;
         if ($InvoiceType == $INVOICE){
     echo 'I am inside a invoice';
     }
     else if ($InvoiceType == 'CREDIT'){
     $PayeeDocumentType = 'CM';echo 'I am inside a credit';
  }
  }

 ---------  Results  --------- 
comparingINVOICEtoINVOICEcomparingINVOICEtoINVOICE

that result doesn't look correct. How can it echo "comparingINVOICEtoINVOICE" twice? — James C
– James C, Commented May 4, 2011 at 19:02
It is a part of a loop. Here are the results: comparingINVOICEtoINVOICEstring(13) "INVOICE" comparingINVOICEtoINVOICEstring(13) "INVOICE" — MG1
– MG1, Commented May 4, 2011 at 19:05

James C · Accepted Answer · 2011-05-04 19:04:40Z

1

My only guess is that $complete[$key][9] is an object and not a string.

What happens if you add print_r($complete[$key][9]) somewhere or modify the 2nd line of code to:

$InvoiceType = (string) $complete[$key][9];

answered May 4, 2011 at 19:04

James C

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1 Comment

MG1 Over a year ago

print_r($complete[$key][9]) prints "INVOICE". I also did gettype and it returned "string"

Sabeen Malik · Accepted Answer · 2011-05-04 20:18:06Z

0

First guess try

$InvoiceType = trim($complete[$key][9]);

Also note the output of the var_dump in "view source" of the page. Basically see the raw output bring sent to the browser, maybe there are some invisible characters there.

answered May 4, 2011 at 20:18

Sabeen Malik

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