Regex for bytes separated by : problem

Question

I have on input hex four byte values separated by : (something like aabbccdd:ffffffff:aaccbbff ). How to construct regex in Java which is going to give answer if input is in correct format or not ?

BalusC · Accepted Answer · 2011-05-04 20:49:00Z

6

How about this?

String value = "aabbccdd:ffffffff:aaccbbff";
boolean match = value.matches("\\p{XDigit}{8}(:\\p{XDigit}{8})*");
// ...

The \p{XDigit} equals to [0-9a-fA-F] by the way. See also the java.util.regex.Pattern javadoc.

answered May 4, 2011 at 20:49

BalusC

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1 Comment

dhblah Over a year ago

"\\p{XDigit}{8}(?::\\p{XDigit}{8})*" would be better - no unnecessary group capturing

pickypg · Accepted Answer · 2011-05-04 20:48:57Z

1

You are looking for this: ^([0-9a-fA-F]{8}:)*([0-9a-fA-F]{8})$

Optional 8 HEX digits followed by a colon (:). Ending with a group without the colon. Probably a way to reduce the RegEx.

answered May 4, 2011 at 20:48

pickypg

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Comments

Andriy M · Accepted Answer · 2011-05-05 20:17:38Z

1

You might try this for arbitrary sequences of 4 bytes: [0-9a-fA-F]{8}(:[0-9a-fA-F]{8})*

edited May 5, 2011 at 20:17

Andriy M

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answered May 4, 2011 at 20:49

Thomas

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