sorting a tuple that contains string and numbers in python

Question

I have a list like this;

List = [('apple 5', 12), ('apple 3', 2), ('apple 6', 10),('apple 4', 15), ('apple 9', 11), ('apple 7', 14), ('apple 18', 10), ('apple 16', 10),('orange 5', 4), ('orange 4', 7)]

I know how to sort the list normally.

for i in sorted(List):
  print(i)

this gives;

('apple 16', 10)
('apple 18', 10)
('apple 3', 2)
('apple 4', 15)
('apple 5', 12)
('apple 6', 10)
('apple 7', 14)
('apple 9', 11)
('orange 4', 7)
('orange 5', 4)

But can I sort something like this?

('apple 3', 2)
('apple 4', 15)
('apple 5', 12)
('apple 6', 10)
('apple 7', 14)
('apple 9', 11)
('apple 16', 10)
('apple 18', 10)
('orange 4', 7)
('orange 5', 4)

Error - Syntactical Remorse · Accepted Answer · 2019-11-17 15:49:56Z

3

You just need to assign your own key:

l1 = [('apple 5', 12), ('apple 3', 2), ('apple 6', 10),('apple 4', 15), ('apple 9', 11), ('apple 7', 14), ('apple 18', 10), ('apple 16', 10),('orange 5', 4), ('orange 4', 7)]

def sort_key(x):
    word, num = x[0].split()
    return word, int(num), x[1] # Sort by word, than the number as an integer, than the final number

l1.sort(key=sort_key)
print(*l1, sep='\n')

Output:

('apple 3', 2)
('apple 4', 15)
('apple 5', 12)
('apple 7', 14)
('apple 9', 11)
('apple 16', 10)
('apple 18', 10)
('orange 4', 7)
('orange 5', 4)

answered Nov 17, 2019 at 15:49

Error - Syntactical Remorse

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Comments

azro · Accepted Answer · 2019-11-17 15:51:00Z

2

You may use your own key to sort, and use multiples criterias, the syntax is sorted(values, key = lambda x: (criteria_1, criteria_2))

values = [('apple 5', 12), ('apple 3', 2), ('apple 6', 10), ('apple 4', 15),
          ('apple 9', 11), ('apple 7', 14), ('apple 18', 10), ('apple 16', 10),
          ('orange 5', 4), ('orange 4', 7)]

for i in sorted(values, key=lambda x: (x[0].split(" ")[0], int(x[0].split(" ")[1]))):
    print(i)

Or using a method to get a proper code

def splitter(v: str):
    s = v.split(" ")
    return s[0], int(s[1])

for i in sorted(values, key=lambda x: splitter(x[0])):
    print(i)

answered Nov 17, 2019 at 15:51

azro

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