I have a recursive function. And i’m looking for what is the time complexity ? Here is the function
public static int f7(int N){
if (N==1) return 0;
return 1 + f7(N/2);
}
I have a recursive function. And i’m looking for what is the time complexity ? Here is the function
public static int f7(int N){
if (N==1) return 0;
return 1 + f7(N/2);
}
First, we come up with a recurrence for this function:
T(1) = 1
T(n) = T(n/2) + 1
This is a recurrence that we can plug into the master theorem, which will give us Θ(log n) as an answer.
Assume that when N=1, the call takes a time units, and when N is a power of 2, it takes b time units, not counting the recursive call.
Then
T(1) = a
T(2^n) = T(2^(n-1)) + b.
This can be seen as an ordinary linear recurrence
S(0) = a
S(n) = S(n-1) + b = S(n-2) + 2b = … = S(0) + nb = a + nb,
or
T(N) = a + Lg(N) b
where Lg denotes the base-2 logarithm.
When N is not a power of 2, the time is the same as for the nearest inferior power of 2.
The exact formula for all N is
T(N) = a + [Lg(N)] b.
Brackets denote the floor function.