Laravel request url with parameter problem with GET Method

Question

I have a route in api.php which look like this:

Route::get('auth/logout/{token}','UserController.php';

I tested this API endpoint using Postman with these configurations:

Method: GET
Params: key = token; value = $2y$10$Xji0VW1Qq9rtF04QlXDu1ePKNKHpRA2ppjDYWNFX.37C30sd3WSIu
Header: none
URL: localhost:8000/api/v1/logout?token=$2y$10$Xji0VW1Qq9rtF04QlXDu1ePKNKHpRA2ppjDYWNFX.37C30sd3WSIu

Here is my UserController@logout:

public function logout($token){
    return response()->json([
        'message' => 'Logout Success',
        'token' => $token
    ], 200);
}

As you can see there, I just want to show a message and the $token parameter in Postman. But my problem is, Postman shows me a blank response. I can't access the URL with ? as the parameter separator. But I can access the URL with /, just like host/api/v1/auth/logout/{token_value}. But it is not what I desired. Anyone can help me?

Dani Fadli · Accepted Answer · 2019-11-19 15:01:34Z

2

You can remove the token route parameter:

Route::get('auth/logout', 'UserController.php');

And retrieve the token from the request in the controller:

public function logout(Request $request) {
    return response()->json([
        'message' => 'Logout Success',
        'token' => $request->token
    ], 200);
}

edited Nov 19, 2019 at 15:01

Dani Fadli

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answered Nov 19, 2019 at 14:56

Remul

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2 Comments

Dani Fadli Over a year ago

Oh, dude!!! Thanks a lot! This is what I searched for. Thanks, @Remul. I am sorry for my edit.

Remul Over a year ago

@DaniFadli You can type-hint the request like it is now, or use the request('token') helper function, both work.

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