how to pass object's function name as a parameter

Question

What I am trying to do is something like this:

def custom_logger(user_logger, log_level, *args, **kwargs):    
    # do some stuff..
    user_logger.log_level(*args, **kwargs)

or like this:

def create_logger(module_name, log_level=DEBUG):
    logger = logging.getLogger(module_name)
    logger.setLevel(logging.log_level)

How can I achieve something like this? Because it will clean up a lot of things.

You are mostly correct, but kwargs should have 2 asterisks: **kwargs. — jknotek
– jknotek, Commented Nov 21, 2019 at 19:07
Is your question how to pass the function name in the caller, or how to use the function name in the callee? — John Gordon
– John Gordon, Commented Nov 21, 2019 at 19:09
@EzizDurdyyev Well, conceptually, yes, it will work. But I don't know anything about how your logger is implemented. So you'll have to try it yourself and debug as needed. — jknotek
– jknotek, Commented Nov 21, 2019 at 19:12
As written, I don't believe this code will work, because it will call literally user_logger.log_level() instead of using whatever function name was passed as the log_level argument. — John Gordon
– John Gordon, Commented Nov 21, 2019 at 19:15

blhsing · Accepted Answer · 2019-11-21 19:17:26Z

1

You can use the getattr function to obtain an attribute by name:

def custom_logger(user_logger, log_level, *args, **kwargs):    
    log = getattr(user_logger, log_level) # or log_level.lower() if log_level is in upper case
    # do some stuff..
    log(*args, **kwargs)

def create_logger(module_name, log_level=DEBUG):
    logger = logging.getLogger(module_name)
    logger.setLevel(getattr(logging, log_level))

edited Nov 21, 2019 at 19:17

answered Nov 21, 2019 at 19:09

blhsing

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2 Comments

Eziz Durdyyev Over a year ago

how can I apply this to create_logger?

Eziz Durdyyev Over a year ago

@blhsubg, did you try it before you answered, or you sure this will work with loggers? again, may be i am doing it wrong but.. it won't work with me. sorry

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