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I have this text in one varchar2 column:

\nAAAA BBB: XXX ZZZ;
\nDDDD DDD: UUU III;
\nAAAA BBB: YYY XXX;
\nDDDD DDD: UUU III;

I have to pull out of the table all the records that have values in the column:

1) XXX in the first place

2) XXX in second place

3) XXX XXX in both place.

I am interested only in sequences of signs beginning with: \nAAAA BBB: do ;

How to do it in Oracle SQL?

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1 Answer 1

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You seem to want a string match. You can do what you describe with LIKE:

select t.*
from t
where col like '\nAAAA BBB:%XXX%'
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