How can I condense this code into a single line? Thanks for the help.
for query in announcements:
try:
query.price = int(query.price)
listme.append(query.price)
except:
print(listme)
-
Do you have a shortage of newline characters in your environment?paxdiablo– paxdiablo2019-11-24 08:00:37 +00:00Commented Nov 24, 2019 at 8:00
-
@Derlin Surprisingly, it can be done. See Ofer Sadan's answer.Aryerez– Aryerez2019-11-24 08:01:28 +00:00Commented Nov 24, 2019 at 8:01
Add a comment
|
1 Answer
This will basically do the same thing, without the printing of failure:
listme.extend(int(query.price) for query in announcements if query.price.isdigit())
This assumes that query.price is a string and that listme is an existing list.
Trying to print the failures as well would be tricky (and unreadable) but possible:
listme.extend(x for x in [int(query.price) if query.price.isdigit() else print(query.price) for query in announcements] if x is not None)
Unless this is a homework assignment or something, it's generally very bad practice to insist that your code fits in one messy unreadable line, so don't do it
3 Comments
αԋɱҽԃ αмєяιcαη
parse_float = lambda x, y=exec("def f(s):\n try:\n return float(s)\n except: return None"): f(x)
Sayandip Dutta
If
query.price is float within string literals, it fails.
Ofer Sadan
@SayandipDutta the code in the question would fail as well. This is equivalent