Detect when user interact with the app (Flutter)

Question

I need a little help there.

I want to disconnect the user from the app when he has been inactive for 5 minutes. So I used this solution : Detect when user is not interacting the app in Flutter

It is perfectly working when the user tap on a widget that is not clickable. For example, when I tap on Text widget, the timer is restarting without an issue, but when I tap on a RaisedButton or ListTile, the timer is not restarting.

So, I'm wondering how it is possible for example with this code :

GestureDetector(
  onTap: () => print("gestureDetector"),
  child: RaisedButton(
    onPressed: () => print("raisedButton"),
  ),
),

to print "gestureDetector" AND "raisedButton".

Thank you in advance for your help, cheers ;)

Btw, I've tried to use IgnorePointer widget or the behavior property of GestureDetector : not working :'( — NqbraL
– NqbraL, Commented Nov 27, 2019 at 10:14

David L. · Accepted Answer · 2019-11-27 10:13:30Z

18

Use a Listener instead of GestureDetector.

Listener(
  onPointerDown: (e) => print('listener'),
  child: RaisedButton(
    onPressed: () => print('raisedButton'),
  ),
),

answered Nov 27, 2019 at 10:13

David L.

8525 silver badges8 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

NqbraL Over a year ago

Wow, thank you for this quick answer and the solution is working fine ! Love u mate :D

user481610 Over a year ago

You sir need a medal. This works very nicely to handle session management.

Collectives™ on Stack Overflow

Detect when user interact with the app (Flutter)

1 Answer 1

2 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related