How can i make a python server open an html file as deafult instead of directory?

Question

here is an example for a simple server:

import http.server
import socketserver

PORT = 80

Handler = http.server.SimpleHTTPRequestHandler

with socketserver.TCPServer(("", PORT), Handler) as httpd:
    print("serving at port", PORT)
    httpd.serve_forever()

the server itself works and the port is open but it opens the directory the code is in while i need it to open an html file that is in that directory.

How can i make it open the html file i want instead of the directory?

do you have index.html in that directory? I just checked your code and if I dont have index.html, it will show the files of that directory. — Nalin Dobhal
– Nalin Dobhal, Commented Nov 27, 2019 at 13:57

Sawant Sharma · Accepted Answer · 2019-11-27 13:58:19Z

6

You can extend SimpleHTTPServer.SimpleHTTPRequestHandler and override the do_GET method to replace self.path with your_file.html if / is requested.

import SimpleHTTPServer
import SocketServer

class MyRequestHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
    def do_GET(self):
        if self.path == '/':
            self.path = '/your_file.html'
        return SimpleHTTPServer.SimpleHTTPRequestHandler.do_GET(self)

Handler = MyRequestHandler
server = SocketServer.TCPServer(('0.0.0.0', 8080), Handler)

server.serve_forever()

More: Documentation

answered Nov 27, 2019 at 13:58

Sawant Sharma

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