Hex in char array

Question

If the following is a one byte array:

char arr[] = "\xFF";

If we do the following:

char arr[] = "\xFFmyrandomstringappendedafterbyte";

printing it would result in this:

byteValueGoesHEREmyrandomstringappendedafterbyte

However, if I try to do the following:

char arr[] = "\xFF98";

It will result in a warning:

warning: hex escape sequence out of range

It treats 98 as part of the hexcode. However, I would it to be treated as a string (as is myrandomstringappendedafterbyte).

I would like to have this as output byteValueGoesHERE98.

How can this be achieved without a whitespace? How can I denote that 98 should be treated as a string?

@KenWhite Apologies, I have updated my question. It was too vague before. — John Doe
– John Doe, Commented Nov 30, 2019 at 1:54
arr[] is not a one byte array. It is a two byte array. 2nd byte is '\0'. — chux
– chux, Commented Nov 30, 2019 at 2:08

aschepler · Accepted Answer · 2019-11-30 02:11:42Z

3

When string literals have only whitespace (or nothing) between them, the preprocessor combines them into a single string literal, but this does not "merge" escape sequences. So you can just write your desired string using two strings:

char arr[] = "\xFF" "98";

This is four bytes including the terminating '\0'.

answered Nov 30, 2019 at 2:11

aschepler

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1 Comment

o11c Over a year ago

Alternatively, note that octal and unicode escapes have a finite length.

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