This is probably a stupid question but is there a way to tell programmatically if the object is jquery or just plain javascript?
For example:
Utils.Listbox.MoveItemsUp = function(listbox) {
if(listbox.isJquery()) {
listbox.each(function(){});
}
else {
for(var i = 0; i < listbox.options.length; i++){}
}
};
jQuery objects have a property called 'jquery':
>>> $('body').jquery
"1.5.2"
jQuery is just Javascript. I guess you could test for the existence of a jQuery function though:
if (foo.each)
{
foo.each(function(...
}
else
{
$(foo).each(function(...
}
One way is to use jQuerys $.isPlainObject function (doc) That will tell you if it was an object created using {} or new Object, a jQuery object will return false. However, note also that an array, and string and functions will also return false:
var obj = {};
var $obj = $('div');
$.isPlainObject(obj); //returns true
$.isPlainObject($obj); //returns false
To test if an object is a jQuery object, you check the jquery attribute of it. so:
<script>
Utils.Listbox.isJquery = function()
{
return typeof this.jquery != 'undefined';
}
</script>
What you should remember is that whenever your within a callback the object this is always an native entity and not a jquery object.
for example:
a = $('a').each(function(){
//'this' is ALWAYS an native object
});
a will always be an instance of jQuery unless your using a specific method that returns a type such as json object, boolean, string etc.
if your recurving variable from a function that's out of your control and you want to know if it's a jQuery object you can do the following:
if(!listbox || !listbox.jquery)
{
listbox = $(listbox)
}
//the variable is now always going to be a jQuery object.
the reason for this is that jquery always stores an reference to its version within a selected context
