How can I let the $foo variable below know that foo should be false?
class foo extends fooBase{
private
$stuff;
function __construct($something = false){
if(is_int($something)) $this->stuff = &getStuff($something);
else $this->stuff = $GLOBALS['something'];
if(!$this->stuff) return false;
}
}
$foo = new foo(435); // 435 does not exist
if(!$foo) die(); // <-- doesn't work :(
You cannot return a value from the constructor. You can use exceptions for that.
function __construct($something = false){
if(is_int($something)) $this->stuff = &getStuff($something);
else $this->stuff = $GLOBALS['something'];
if (!$this->stuff) {
throw new Exception('Foo Not Found');
}
}
And in your instantiation code:
try {
$foo = new foo(435);
} catch (Exception $e) {
// handle exception
}
You can also extend exceptions.
catch it. You can do anything you want from that point.
if ( $foo->is_falid() ){ /* do stuff */} , and please stop abusing die() function.Constructor is not supposed to return anything.
If you need to validate data before using the to create an object, you should use a factory class.
Edit: yeah , exceptions would do the trick too, but you should not have any logic inside the constructor. It becomes a pain for unit-testing.
You can try
<?php
function __construct($something = false){
$this->stuff = $something;
}
static function init($something = false){
$stuff = is_int($something) ? &getStuff($something) : $GLOBALS['something'];
return $stuff ? new self($stuff) : false;
}
$foo = foo::init(435); // 435 does not exist
if(!$foo) die();
