In java replace the regex with string

Question

In java I am using regex \".*?\". I used this for replacing all the string with doublequote with a term String.

Ex:
INPUT: Functions.unescapeJson("test")
Result : Functions.unescapeJson("String")

But now I wanted to exclude some string if they contains double quote. So, I am using / as the escape character. How to achieve this.

Ex:
INPUT: Functions.getJsonPath(Functions.getJsonPath(Functions.getJsonPath(Functions.unescapeJson("test"), "m2m:cin.con"),"payloads_ul.dataFrameOutput"),"[/"Dimming Value/"]")

RESULT: Functions.getJsonPath(Functions.getJsonPath(Functions.getJsonPath(Functions.unescapeJson(String), String),String),String)

But the result I am getting if I use the previous regex is:

Functions.getJsonPath(Functions.getJsonPath(Functions.getJsonPath(Functions.unescapeJson(input.mIntegerm/:sgn.nev.rep), String),String),StringDimming ValueString)

How to achieve this using regex if it finds / it should neglect without replacing original string.

The code that I am using

public static void main(String[] args) {
    String STRINGVALIDATIONREGEX = "\".*?\"";
    String formula = "Functions.getJsonPath(Functions.getJsonPath(Functions.getJsonPath(Functions.unescapeJson(input.m2m/:sgn.nev.rep), \"m2m:cin.con\"),\"payloads_ul.dataFrameOutput\"),\"[\"Dimming Value\"]\")";
    System.out.println(formula.replace(STRINGVALIDATIONREGEX, "String"));
}

Donat · Accepted Answer · 2019-12-15 14:00:46Z

1

You can use this regex:

\"(\/?.)*?\"

answered Dec 15, 2019 at 14:00

Donat

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LeoMurillo · Accepted Answer · 2019-12-15 14:07:44Z

1

Use [^/] to match anything that is not a slash.

For example, [^/]?\".*[^/]?\" would catch quotes not preceded by /

answered Dec 15, 2019 at 14:07

LeoMurillo

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Booboo · Accepted Answer · 2019-12-15 16:34:46Z

1

"((?:[^"]|(?<=\/)")*)"

" match a "
[^"] match a non-quote character
| or
(?<=\/)") a quote character that is preceded by a /
* match sub-expressions 2 - 4 zero or more times.
" match a "

See Regex demo

If you believe that a string such as "abc/" is invalid, then you should use the stricter regex:

"((?:[^"\/]|\/")*)"

" match "
[^"\/] match a any character that isn't a quote for /
| or
\/" match a /" combination
* match sub-expressions 2 - 4 zero or more times.
" match a "

See Regex demo

edited Dec 15, 2019 at 16:34

answered Dec 15, 2019 at 16:14

Booboo

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