How do I return JSON response in Class based views, instead of HTTP response

Question

I have a class based view. I am using Ajax on a bootstrap modal. To avoid page refresh, I want to return JSON response instead of HTTP response with this class based view- but I have only seen how to return JSON response for function based views.

views.py:

from django.contrib.auth.mixins import LoginRequiredMixin

class TaskCreateView(LoginRequiredMixin, CreateView):
    template_name = 'create.html'
    form_class = TaskForm
    success_url = reverse_lazy('task_list')

    def get_form_kwargs(self):
        kwargs = super().get_form_kwargs()
        kwargs.update(user=self.request.user)
        return kwargs

Override the post(...) method of CBV

JPG
– JPG

2020-01-08 12:08:39 +00:00
Commented Jan 8, 2020 at 12:08 — JPG
– JPG, Commented Jan 8, 2020 at 12:08

Dmitry Leiko · Accepted Answer · 2020-01-08 12:17:42Z

5

Try code below:

from django.contrib.auth.mixins import LoginRequiredMixin
from django.http import JsonResponse

class TaskCreateView(LoginRequiredMixin, CreateView):
    template_name = 'create.html'
    form_class = TaskForm
    success_url = reverse_lazy('task_list')

    def get_form_kwargs(self):
        kwargs = super().get_form_kwargs()
        kwargs.update(user=self.request.user)
        return kwargs

    def form_valid(self, form):
        return JsonResponse({'foo':'bar'})

answered Jan 8, 2020 at 12:17

Dmitry Leiko

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Comments

Shavzz Hussain · Accepted Answer · 2020-01-08 12:16:03Z

1

Try this: works for me. actually you have to override the post method if you are stick with Class-based Views.

import json

class TaskCreateView(LoginRequiredMixin, CreateView):
    form_class = TaskForm
    success_url = reverse_lazy('task_list')

...

def post(self, request, **kwargs):
     response_data = 'your data'

    return HttpResponse(json.dumps(response_data),content_type="application/json")

answered Jan 8, 2020 at 12:16

Shavzz Hussain

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