Injecting the result of PHP code into a Javascript alert box

Question

I've recently been designing a website for a client, and have run into a slight difficulty in Javascript - I need to have either a <?php include()?>, or a form (the former being of more use) within a Javascript alert box.

Is there any way to do this? Thanks. :)

Do you mean have custom input fields in an alert popup, like the one you get when you do alert("string"); Or like a form in a modal that pops over the rest of the content on the page? — Tom Chandler
– Tom Chandler, Commented May 11, 2011 at 22:11

SLaks · Accepted Answer · 2011-05-11 22:10:31Z

1

The alert function can only show plain text.

You need to use a fake modal dialog, such as jQuery UI Dialog.

answered May 11, 2011 at 22:10

SLaks

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Nicole · Accepted Answer · 2011-05-11 22:11:08Z

0

One PHP page:

<script type="text/javascript">
alert("<?php include("otherpage.php"); ?>");
</script>

otherpage.php:

echo "Hello, world";

Of course, the output of otherpage.php can only be plain text, and must have properly escaped quotes. If you need to do anything else, you will need a different solution than JavaScript's alert.

answered May 11, 2011 at 22:11

Nicole

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1 Comment

Frank Farmer Over a year ago

You'd need to be very careful about the output of your PHP include, or capture it and escape it for use in a javascript context.

fl3x7 · Accepted Answer · 2011-05-11 22:15:35Z

0

Does it have to be an alert box? Can it not be a lightbox?

The jquery UI dialog box may be of some help. it hasa dialog box with a form

jQuery UI Dialog Box

Personally if you want a form in a box to pop up on click or something I would use a lightbox.

Hope this helps,

answered May 11, 2011 at 22:15

fl3x7

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