Printing individual variable of a structure in gdb

Question

I'm debugging the Linux kernel. I can print the content of a structure like this:

(gdb) p *(struct rb_node*)0xffff88813b160388
 $6 = {
 __rb_parent_color = 1, 
 rb_right = 0xffff88813b31a5c8, 
 rb_left = 0xffff88813b1608c8
}

Instead of printing the whole structure content, I'm trying to print a particular value of a structure. For example, something like, rb_right = 0xffff88813b31a5c8. I try the following way, it shows me an error, I'm not quite sure if this is the right approach or not.

(gdb) p *((struct rb_node*)rb_right) 0xffff88813b160388
 No symbol "rb_right" in current context.

Please help.

Maneevao · Accepted Answer · 2020-01-23 12:47:36Z

1

It's a structure, use C syntax:

p (*(struct rb_node*) 0xffff88813b160388).rb_right

answered Jan 23, 2020 at 12:47

Maneevao

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