Comparing two arrays with objects with unordered keys

Question

I know they're several questions that indicate how to do this, however, when the keys of the objects are in a different order the provided solutions do not work.

let array1 = [
  { name: 'David', age: 30 },
  { name: 'Amy', age: 39 }
];

let array2 = [
  { age: 30, name: 'David' },
  { age: 39, name: 'Amy' }
];

Comparing the arrays

console.log(array1.every((value, index) => {
   return JSON.stringify(value) === JSON.stringify(array2[index]);
})

// Returns false
// Expected true

Understandably these two arrays are different but the data is the same. So...

How do I compare arrays with objects in which I cannot guarantee that the keys are ordered identically?

For checking equality of two JS objects, refer this: stackoverflow.com/questions/201183/… — Ajay Dabas
– Ajay Dabas, Commented Feb 4, 2020 at 3:46
stringify is failing here because of generating different strings due to the different ordering of keys. — Ajay Dabas
– Ajay Dabas, Commented Feb 4, 2020 at 3:47

Hao Wu · Accepted Answer · 2020-02-04 04:00:19Z

2

You can do a proper object comparison, there are a lot of ways to do that.

Here's one of the examples:

let array1 = [
  { name: 'David', age: 30 },
  { name: 'Amy', age: 39 }
];

let array2 = [
  { age: 30, name: 'David' },
  { age: 39, name: 'Amy' }
];

console.log(array1.every((value, index) => 
  Object.keys(value).length === Object.keys(array2[index]).length &&
  JSON.stringify(value) === JSON.stringify({...value, ...array2[index]})
));

edited Feb 4, 2020 at 4:00

answered Feb 4, 2020 at 3:52

Hao Wu

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Comments

Siva Kondapi Venkata · Accepted Answer · 2020-02-04 04:32:13Z

0

1) Convert array of objects to array of strings
2) Compare both array of strings (one way is to do with reduce as below).

let array1 = [
  { name: "David", age: 30 },
  { name: "Amy", age: 39 }
];

let array2 = [
  { age: 30, name: "David" },
  { age: 39, name: "Amy" }
];


const isEqual = (arr1, arr2) => {
  if (arr1.length !== arr2.length) {
    return false;
  }
  const toStr = ({ name, age }) => `${name}-${age}`;
  const a1 = Array.from(arr1, toStr);
  const a2 = Array.from(arr2, toStr);
  return a1.every(item => a2.includes(item));
};

console.log(isEqual(array1, array2));

answered Feb 4, 2020 at 4:32

Siva Kondapi Venkata

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