How do I include/exclude a JUnit 5 `ParameterizedTest` by name in Maven

Question

I have a parameterized JUnit 5 test, e.g.

@EnumSource(Mode.class)
@ParameterizedTest void shouldRunWithMode(Mode mode) {
    ...

I want to exclude one of the enum cases from running in Maven, as described here:

<plugin>
    <artifactId>maven-surefire-plugin</artifactId>
    <version>2.22.2</version>
    <configuration>
        <test>!testpackage.SomeTest#shouldRunWithMode[3 three]</test>
    </configuration>
</plugin>

The same thing without the ! would mean inclusion, i.e. execute only this test.

I played around with the exclude expression and the square brackets, but I didn't find a combination to make it work.

A demo project is on GitHub.

First I recommend to upgrade to most recent version of maven-surefire-pugin cause there had been improvements related to JUnit Jupiter platform...cause you are referencing version 2.22.2 but the docs are 3.0.0-M4 ... — khmarbaise
– khmarbaise, Commented Feb 6, 2020 at 7:49
Thanks for the hint, @khmarbaise. That's a milestone release, but worth giving a try... but it didn't help :-/ — rü-
– rü-, Commented Feb 7, 2020 at 8:17
Check the syntax cause your example gives the package testpackage instead of pkg/.. furthermore I would check to use SomeTest.class#shouldRunWithMode... — khmarbaise
– khmarbaise, Commented Feb 7, 2020 at 10:21
I only have a testpackage, no pkg. And adding .class didn't help. — rü-
– rü-, Commented Feb 8, 2020 at 13:55
You are using a dot instead of / see the documentation.... — khmarbaise
– khmarbaise, Commented Feb 8, 2020 at 14:12

rü- · Accepted Answer · 2020-02-19 10:49:22Z

0

I dug into the code and found that there is no code for it. It's obviously supported only on JUnit 4.

I reported it as a bug SUREFIRE-1753

answered Feb 19, 2020 at 10:49

rü-

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