Remove a element from List of objects based on inner object list value in java

Question

How can I remove the element from the list if some inner list attribute value fails to meet the condition.The trick here is that attribute is itself a list and comparison is based on some attribute of that inner list. Please refer the below sample and help out to fill the comment section in code:

Object :

Class product{
 private String productId;
 private String productName;
 private List<Attribute> attributeList;

    public static class Attribute{
        private Long attributeId;
    }
}

Driver class :

Class Driver{
   List<product> productList = new ArrayList<product>();
   /*
   Remove the object from productList if attributeList doesn't contain attribute with attributeId = x;
*/
}

productList.removeIf(p -> p.getAttributeList().stream().map(Attribute::getAttributeId) .noneMatch(Predicate.isEqual(x))); — Holger
– Holger, Commented Feb 18, 2020 at 17:51

Anton Balaniuc · Accepted Answer · 2020-02-18 17:32:38Z

5

What you can do it to stream over original list, and leave only objects which satisfy the condition. It might look something like this:

List<Product> filtered = productList.stream()
      .filter( p -> p.attributeList().stream().anyMatch( a -> a.attributeId.equals(x))
      .collect(Collectors.toList())

in this live we are actually checking if nested list contains at least one object with attributeId = x p.attributeList().stream().anyMatch( a -> a.attributeId.equals(x)

answered Feb 18, 2020 at 17:32

Anton Balaniuc

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Comments

Moises Cavcalcanti · Accepted Answer · 2020-02-18 17:43:58Z

1

You can do a foreach loop and remove the unwanted elements. In "product" class you can insert a "FindInnerAtribute" function to search inside the Attributes list and return true if there is some.

List<product> productList = new ArrayList<product>();
for(product p : productList){
    if ( p.FindInnerAttribute(x) ){
        productList.remove(p);
    }
}

How to remove from list

answered Feb 18, 2020 at 17:43

Moises Cavcalcanti

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1 Comment

Holger Over a year ago

Calling remove on the list while you're iterating over it, is broken. In the best case, you get an exception.

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