This is my code:
fun main(){
val str = "123"
println(str.toInt()) // 123
println(str[1].toInt()) // 50 ???
}
I want number 2. But it's result number 50.
I didn't want ASCII code number.
How can I get a solution?
2 Answers
If you want to get the second character in the String, you can do
println(str[1])
And if you want to convert the second character to an Int, then you should do
println(str[1].toString().toInt())
Please note that toInt() can throw a NumberFormatException.
1 Comment
msm082919
I thought str [n] returned a string. Now I know that str [n] returns a character. Thank you.
The ASCII value of character '2' is 50 (decimal). Looks like you want a substring operation to get the string "2" (or "23" ?) rather than character indexing that gets the char '2'.
str[1]. What does that say?