I have tried as below , it can be done using list comprehension [also without using in-build functions and techniques like [::-1] ], but want to do it using nested for loops as below ?
l=['temp','test']
l1=[]
for t in l:
for i in t:
l1.append(str(i[::-1]))
print(l1)
input: ['test','temp']
required output : ['pmet','tset']
In order to reverse the order of the elements in the list, you can use reverse:
for i in reversed(array):
print(i)
Or, you can use array.reverse().
in order to reverse each string, you can use [::-1], for example:
txt = "Hello World"[::-1]
print(txt)
output:
dlroW olleH
Looking at the code you added, you can do something like this:
l=['temp','test']
reverse_l=[]
reverse_l = [item[::-1] for item in l] # This is list comprehensions, you can read about it in the link at the end of the answer
reverse_l.reverse()
print(l)
print(reverse_l)
output:
['temp', 'test']
['tset', 'pmet']
A solution without list comprehension:
l=['temp','test']
reverse_l=[]
for item in l:
item = item[::-1]
reverse_l.append(item)
reverse_l.reverse()
print(l)
print(reverse_l)
You can find information about list Comprehensions in python here.
Using nested loops:
l=['temp','test']
print([''.join([w[i] for i in range(len(w)-1, -1, -1)]) for w in reversed(l)])
Output:
['pmet', 'tset']
try this
l=['temp','test']
l1=[]
for t in l:
l1.append(t[::-1])
print(l1)
You don't need a nested loop:
l = ['temp', 'test']
l1 = [
word[::-1]
for word in l
]
print(l1)
output:
['pmet', 'tset']
You can try the following :
input_list = ['test', 'temp']
input_list.reverse()
print(list(map(lambda x: x[::-1], input_list)))
for i in range(len(l)):
l[i] = l[i][::-1]
l = l[::-1]
you don't need nested loops for desired output you have given.
