I'm using the following single line of python code to print out a specific pattern which I showed at the bottom.
My code:
print(*[a, b, for a in range(5): for b in range(3)], sep='\n')
After executing the above code, I'm getting an invalid syntax error but I could not find any syntax error there.
Error:
Getting error : SyntaxError: invalid syntax
My desired output as follow:
1 1 1 2 1 3 1 4 2 1 2 2 2 3 2 4
How can I print this pattern in a single line of code?
I appreciate your assistance.
Go for:
print(*[f'{a} {b}' for a in range(5) for b in range(3)], sep='\n')
0 0
0 1
0 2
1 0
1 1
1 2
...
{} is evaluated e.g. print(f'1+2={1 + 2}') prints '1+2=3'
Another thing that other answers don't have into account is that, in order to have the pattern that you are looking for, range should start at 1 and a and b should change places.
print(*["{} {}".format(a,b) for a in range(1, 3) for b in range(1, 5)], sep='\n')
You have made two syntax errors in your list comprehension
In a list comprehension the for loop is not an expression so you don't write the colon:.
You want to store a string in the list comprehension. The expression that is stored by the list comprehension is not part of the print function. There are multiple ways of constructing the string. In this case f-strings are a good solution.
The correct syntax is
print(*[f"{a} {b}") for a in range(5) for b in range(3)], sep='\n')
If a list comprehension becomes too long, i tend to split it over multiple lines.
data = [
f"{a} {b}"
for a in range(5)
for b in range(3)
]
print(*data, sep="\n")
print(*[(a, b) for a in range(5) for b in range(3)], sep='\n')Of course that only solves the error, not the formatting - but the string formatting was already explained by others. :)