How to get data from Collection Map in discord.js

Question

For my bot in discord, I would like a !help command that loops through all commands, gets the name, and returns them in a message back to the user. I have created fs to loop through my /commands/ folder:

for (const file of commandFiles) {
    const command = require(`./commands/${file}`);
    client.extraCommands.set(command.name, command);
}

console.log(client.extraCommands);

Returns a Collection Map that looks like: (cropped for sake of simplicity)

Collection [Map] {
  'args-info' => {
    name: 'args-info',
    execute: [Function: execute]
  },
  'channel-info' => {
    name: 'channel-info',
    execute: [Function: execute]
  }

All I need is to store the name of each command into an array.

I've tried looping through to get the key but that doesn't seem to work...

Thanks in advance for any help

If it's a Map, you can loop through for(const key of client.extraCommands.keys()){/* Add key to an array */} or just use client.extraCommands.keys() since it's an iterator — xxMrPHDxx
– xxMrPHDxx, Commented Mar 9, 2020 at 21:20

Simon Polak · Accepted Answer · 2020-03-09 21:21:43Z

3

Looks like the key names are your command names, so this should do the trick.


let keys = Array.from(client.extraCommands.keys());

answered Mar 9, 2020 at 21:21

Simon Polak

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Herbie Vine · Accepted Answer · 2020-03-24 11:17:38Z

1

So, at first, I thought I should make a loop to go through all files and get the 'name' attribute. However, the .keys() returns an array for all properties inside the map Documentation

edited Mar 24, 2020 at 11:17

answered Mar 16, 2020 at 13:39

Herbie Vine

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1 Comment

Simon Polak Over a year ago

I never said you need to loop yourself to get the keys.

Sunny · Accepted Answer · 2020-03-09 21:29:25Z

0

Both lines of codes will return the same result as you want.

[...client.extraCommands.keys()] //using map keys
[...client.extraCommands.values()].map(({name})=> name); // using key 'name' from each map value

answered Mar 9, 2020 at 21:29

Sunny

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