Encode json file using with open

Question

I am using with open to open my json file and parse data from it, however some characters aren't ascii. I google around and found that you have to set encoding='utf8' in with open(), so I do this and get this error

UnicodeEncodeError: 'ascii' codec can't encode character '\xf6' in position 21: ordinal not in range(128)

So I figure I have to use ensure_ascii=False but then I get this error

TypeError: 'ensure_ascii' is an invalid keyword argument for open()

As you can see by the error ensure_ascii isn't compatible with open() but I don't know what is and I seem to be stuck and unable to find it.

The code being used

with open("languages.json", 'r', encoding='utf8') as f:
    languages = json.load(f)
with open("config.json", 'r', encoding='utf8') as c:
    config = json.load(c)

Which python version and json package you've used? Python 3 uses UTF-8 for opening by default and ensure_ascii is a param for json. — frost-nzcr4
– frost-nzcr4, Commented Mar 12, 2020 at 11:42
ensure_ascii is a param for json.dump that opposites of load, also not all json packages implement it. So it's not your case either. Try to do data = f.read(); json.loads(data). — frost-nzcr4
– frost-nzcr4, Commented Mar 12, 2020 at 11:49

damaredayo · Accepted Answer · 2020-03-12 10:43:04Z

1

I believe that utf8 is not the correct keyword, instead use utf-8 in your encoding=

answered Mar 12, 2020 at 10:43

damaredayo

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4 Comments

damaredayo Over a year ago

Could you show me any of the .json files? Also, don't use ensure_ascii; there's no need.

Real123 Over a year ago

"deutsch": { "2": "Subject: Antrag auf Löschung personenbezogener Daten } is one of them

damaredayo Over a year ago

This line here works fine for me: with open("test.json", "r", encoding="UTF-8") as i: where test.json is {"deutsch": { "2": "Subject: Antrag auf Löschung personenbezogener Daten" }}

frost-nzcr4 Over a year ago

There is no difference in spelling between utf8, utf-8, and UTF-8 for Python.

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