Regex matching newline character by default in python

Question

I want to check whether the given string input is a number of six digits.

Valid:

* 123456
* 098765

Invalid:

* 123
* 12345a
* as3445
* /n123456
* 123456\n

My Python code:

bool(re.match("^[0-9]{6}$",string))

but this also matches "123456\n".

Why it is matching newline character and how to restrict this match?

You could use ^[0-9]{6}\Z

The fourth bird
– The fourth bird

2020-03-21 08:36:23 +00:00
Commented Mar 21, 2020 at 8:36 — The fourth bird
– The fourth bird, Commented Mar 21, 2020 at 8:36

azro · Accepted Answer · 2020-03-21 08:48:22Z

1

As proposed in comment, \Z : asserts position at the end of the string, or before the line terminator right at the end of the string

values = ["123456", "098765", "Invalid:", "123", "12345a", "as3445", "/n123456", "123456\n"]
for v in values:
    print("{:10s} {}".format(v, bool(re.match("^[0-9]{6}\Z", v))))


123456     True
098765     True
Invalid:   False
123        False
12345a     False
as3445     False
/n123456   False
123456
    False

answered Mar 21, 2020 at 8:48

azro

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