I'm trying to break a forloop using break as traditional, but in this case I find myself stuck with this nested switch where the break only works into the switch scope and the loop keeps iterating.
for (int i = 0; i < lenght; i++)
{
switch (enum)
{
case Enum.some_1: break;
case Enum.some_2: break;
case Enum.some_3: break;
}
}
There are multiple options to approach this:
bool exit = false;
for (int i = 0; i < length && !exit; i++)
{
switch(enum)
{
case Enum.case_which_breaks:
exit = true;
break;
// other cases
}
// some other code, which may use `i`
}
This would be simpler, if you could refactor out the whole for block into a helper method. In this case, you'll use return rather than break.
private Result HandleInternally(int length, Enum enum, Request params)
{
for (int i = 0; i < length; i++)
switch (enum)
{
case Enum.case_which_breaks:
Result result = new Result(); //populate the result
return result;
// other cases
}
}
And then in the consuming code simply call the method.
bool exitForLoop = false;
for (int i = 0; i < length && !exitForLoop; i++)
{
switch (enum)
{
case Enum.some_1: exitForLoop = true; break;
case Enum.some_2: break;
case Enum.some_3: break;
}
}
bool exit = false;
int i = 0;
while (!exit && i < length)
{
switch (enum)
{
case Enum.some_1: exit = true; break;
case Enum.some_2: exit = true; break;
case Enum.some_3: exit = true; break;
}
i++;
}
forloop because you are not even using he index "i" in any way. You appear to be iterating over an array or list, but you have not provided enough information.