How to read three variables using scanf in C?

Question

I am writing a simple calculator. I want to read first integer and save it in el1. Then I want to print "Enter el2: \n" and after this read the second integer and save it in el2. After this I need to print "Choose from ( + , - , / , * )" and read it and save in op[0]. My program is printing Enter el1: and then it waits for me to input 2 integers, then it pronts Enter el2: and waits for me to input 1 integer and then prints Choose from.. and reads nothing.

int el1 = 0;
printf("Enter el1:  \n");
scanf(" %d \n", &el1);
int el2 = 0;
printf("Enter el2: \n");
scanf(" %d \n", &el2);
printf("Choose from ( + ,  - ,  / , * ):\n");
char op[2];
scanf("%c", &op[0]);

How to make it work properly?

do not add spaces (tabs, newlines, ...) after "%d" (or "%c" or "%[]" or "%s"...) in scanf. Even better: stop using scanf for user input. — pmg
– pmg, Commented Apr 4, 2020 at 8:34
Ok, I added a space before %c, why now it works? I don't understand the logic of it.Edit; Thanks. I didn't see that comment. — user12421869
– user12421869, Commented Apr 4, 2020 at 8:47

hanie · Accepted Answer · 2020-04-04 08:48:16Z

1

as mentioned in comments remove white spaces from scanf .otherwise it will wait for you to enter a non-white space character.

and add one space here scanf(" %c", &op[0]); , because it prevent scanf to take \n in buffer as input.

look

printf("Enter el1:  \n");
scanf("%d", &el1);
int el2 = 0;
printf("Enter el2: \n");
scanf("%d", &el2);
printf("Choose from ( + ,  - ,  / , * ):\n");
char op[2];
scanf(" %c", &op[0]);

answered Apr 4, 2020 at 8:48

hanie

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