I want to get each item in the list 'spam' but i an not able to call spam list..
spam = ['apples' , 'bananas' , 'tofu' , 'cats']
i = 0
n = len(spam)
for i in range (0, n):
if i <= n :
print(spam(i) , end = ',')
i += 1
else:
break
Traceback (most recent call last):
File "C:\Users\admin\AppData\Local\Programs\Python\Python38\commaCode.py", line 9, in <module>
print(spam(i) , end = ',')
TypeError: 'list' object is not callable
As the error message points out, list objects are not callable.
You should access the items of your list with square brackets (i.e. spam[i] instead of spam(i)).
Also, when iterating on a list, you can avoid using range most of the time:
spam = ['apples' , 'bananas' , 'tofu' , 'cats']
for thing in spam:
print(thing , end = ',')
List slicing in python works like this spam[i], using normal brackets on something always means "calling" it, meaning treating it like a function to be called.
Your problem here is with this line:
print(spam(i) , end = ',')
In this instance, since you've encased i within rounded brackets, Python attempts to execute spam() as a Function while passing i as an argument. To fix this, use square brackets instead:
print(spam[i] , end = ',')
whileloop to aforloop? You seem to have missed some crucial parts of aforloop withrange. You don't need theif, you don't need to incrementimanually and you don't needbreak. In fact, you don't even need thei. Please read the answer of @tyrion below.